1.6 Compressed Liquid Approximation

Problem Statement:

For water at 50°C under high pressure, approximate the specific volume, internal energy, enthalpy, and entropy assuming it behaves as a compressed liquid.

## Solution:

import CoolProp.CoolProp as CP

# Given values
T = 50 + 273.15  # Temperature in Kelvin

# Approximations for compressed liquid
v = CP.PropsSI('D', 'T', T, 'Q', 0, 'Water')  # Specific volume
u = CP.PropsSI('U', 'T', T, 'Q', 0, 'Water')/1e3  # Specific internal energy
h = CP.PropsSI('H', 'T', T, 'Q', 0, 'Water')/1e3  # Specific enthalpy
s = CP.PropsSI('S', 'T', T, 'Q', 0, 'Water')/1e3  # Specific entropy

# Output the results
print(f"Specific volume: {round(v,2)} m^3/kg")
print(f"Specific internal energy: {round(u,2)} kJ/kg")
print(f"Specific enthalpy: {round(h,2)} kJ/kg")
print(f"Specific entropy: {round(s,2)} kJ/kg*K")

Specific volume: 988.0 m^3/kg
Specific internal energy: 209.33 kJ/kg
Specific enthalpy: 209.34 kJ/kg
Specific entropy: 0.7 kJ/kg*K