1.4 Enthalpy of a Steam

Problem Statement:

Calculate the specific enthalpy of steam at a pressure of 200 kPa and a specific volume of 0.15 m³/kg.

## Solution:

import CoolProp.CoolProp as CP

# Given values
P = 200000  # Pressure in Pascals
v = 0.15  # Specific volume in m^3/kg

# Specific enthalpy calculation
h = CP.PropsSI('H', 'P', P, 'D', 1/v, 'Water')

# Output the result
print(f"Specific enthalpy of steam: {round(h/1e3,1)} kJ/kg")

Specific enthalpy of steam: 875.4 kJ/kg